1/(x^2-2x-3)-3/(2x^2-18)=1/(x^2+4x+3)

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Solution for 1/(x^2-2x-3)-3/(2x^2-18)=1/(x^2+4x+3) equation:


D( x )

x^2+4*x+3 = 0

2*x^2-18 = 0

x^2-(2*x)-3 = 0

x^2+4*x+3 = 0

x^2+4*x+3 = 0

x^2+4*x+3 = 0

DELTA = 4^2-(1*3*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-4)/(1*2) or x = (-4^(1/2)-4)/(1*2)

x = -1 or x = -3

2*x^2-18 = 0

2*x^2-18 = 0

2*x^2 = 18 // : 2

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x^2-(2*x)-3 = 0

x^2-(2*x)-3 = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(1*2) or x = (2-16^(1/2))/(1*2)

x = 3 or x = -1

x in (-oo:-3) U (-3:-1) U (-1:3) U (3:+oo)

1/(x^2-(2*x)-3)-(3/(2*x^2-18)) = 1/(x^2+4*x+3) // - 1/(x^2+4*x+3)

1/(x^2-(2*x)-3)-(3/(2*x^2-18))-(1/(x^2+4*x+3)) = 0

1/(x^2-2*x-3)-3*(2*x^2-18)^-1-(x^2+4*x+3)^-1 = 0

1/(x^2-2*x-3)-3/(2*x^2-18)-1/(x^2+4*x+3) = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

x^2-2*x-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(1*2) or x = (2-16^(1/2))/(1*2)

x = 3 or x = -1

(x+1)*(x-3) = 0

x^2+4*x+3 = 0

x^2+4*x+3 = 0

x^2+4*x+3 = 0

DELTA = 4^2-(1*3*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)-4)/(1*2) or x = (-4^(1/2)-4)/(1*2)

x = -1 or x = -3

(x+3)*(x+1) = 0

1/((x+1)*(x-3))-3/(2*x^2-18)-1/((x+3)*(x+1)) = 0

(1*(2*x^2-18)*(x+3))/((x+1)*(x-3)*(2*x^2-18)*(x+3))+(-3*(x+1)*(x-3)*(x+3))/((x+1)*(x-3)*(2*x^2-18)*(x+3))+(-1*(x-3)*(2*x^2-18))/((x+1)*(x-3)*(2*x^2-18)*(x+3)) = 0

1*(2*x^2-18)*(x+3)-3*(x+1)*(x-3)*(x+3)-1*(x-3)*(2*x^2-18) = 0

3*x^2-x^3-2*x^3+6*x^2+9*x+18*x-54-27 = 0

9*x^2-3*x^3+27*x-81 = 0

9*x^2-3*x^3+27*x-81 = 0

3*(3*x^2-x^3+9*x-27) = 0

3*x^2-x^3+9*x-27 = 0

{ 1, -1, 3, -3, 9, -9, 27, -27 }

1

x = 1

3*x^2-x^3+9*x-27 = -16

1

-1

x = -1

3*x^2-x^3+9*x-27 = -32

-1

3

x = 3

3*x^2-x^3+9*x-27 = 0

3

x-3

9-x^2

3*x^2-x^3+9*x-27

x-3

x^3-3*x^2

9*x-27

27-9*x

0

9-x^2 = 0

DELTA = 0^2-(-1*4*9)

DELTA = 36

DELTA > 0

x = (36^(1/2)+0)/(-1*2) or x = (0-36^(1/2))/(-1*2)

x = -3 or x = 3

x in { -3, 3, 3}

3*(x+3)*(x-3)^2 = 0

(3*(x+3)*(x-3)^2)/((x+1)*(x-3)*(2*x^2-18)*(x+3)) = 0

(3*(x+3)*(x-3)^2)/((x+1)*(x-3)*(2*x^2-18)*(x+3)) = 0 // * (x+1)*(x-3)*(2*x^2-18)*(x+3)

3*(x+3)*(x-3)^2 = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -3}

x in { 3}

x belongs to the empty set

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